Array Questions
- Longest Continuous Increasing Subsequence
Question
Original Question: Leetcode 674. Longest Continuous Increasing Subsequence
Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).
Example 1:
Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3.
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1.
Solution
- Java
- Python
class Solution {
public int findLengthOfLCIS(int[] nums) {
if(nums.length == 0) return 0;
int dp[] = new int[nums.length];
dp[0] = 1;
int res = 1;
for(int i = 1; i < nums.length; i++){
if(nums[i] > nums[i-1]){
dp[i] = dp[i-1]+1;
} else {
dp[i] = 1;
}
res = Math.max(dp[i], res);
}
return res;
}
}
class Solution(object):
def findLengthOfLCIS(self, nums):
if not nums:
return 0
dp = [1] * len(nums)
for i in range(1, len(nums)):
if nums[i] > nums[i-1]:
dp[i] = dp[i - 1] + 1
return max(dp)